Riddhish Bhalodia
Last Activity: 9 Years ago
There are total of 11 steps from 0 to 10 so if lets suppose at every counter there was tails and hence the counter increments by 2 at every step and hence the total would be 22. It is an obvious reasoning from here that to get 23 as the counter value there must be an heads toss at ONLY ONE out of total 11 steps.
So the probablity of having 10 tails and 1 head sequenceis
